2-7/a=-3/a^2

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Solution for 2-7/a=-3/a^2 equation: 


D( a )

a^2 = 0

a = 0

a^2 = 0

a^2 = 0

1*a^2 = 0 // : 1

a^2 = 0

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

2-(7/a) = -3/(a^2) // + -3/(a^2)

2-(7/a)-(-3/(a^2)) = 0

3*a^-2-7*a^-1+2 = 0

t_1 = a^-1

3*t_1^2-7*t_1^1+2 = 0

3*t_1^2-7*t_1+2 = 0

DELTA = (-7)^2-(2*3*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+7)/(2*3) or t_1 = (7-25^(1/2))/(2*3)

t_1 = 2 or t_1 = 1/3

t_1 = 1/3

a^-1-1/3 = 0

1*a^-1 = 1/3 // : 1

a^-1 = 1/3

-1 < 0

1/(a^1) = 1/3 // * a^1

1 = 1/3*a^1 // : 1/3

3 = a^1

a = 3

t_1 = 2

a^-1-2 = 0

1*a^-1 = 2 // : 1

a^-1 = 2

-1 < 0

1/(a^1) = 2 // * a^1

1 = 2*a^1 // : 2

1/2 = a^1

a = 1/2

a in { 3, 1/2 }

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